Answer :

Given: equation is perpendicular to lx + my + n = 0 and passing through (α, β)


To find:


The equation of the straight line through the point (α, β) and perpendicular to the line lx + my + n = 0.


Explanation:


The line perpendicular to lx + my + n = 0 is


mx – ly + λ = 0


This line passes through (α, β).


mα-lβ + λ = 0 λ = lβ-mα


Substituting the value of λ:


mx – ly + lβ-mα = 0


mx – α = ly – β


Hence, equation of the required line is mx – α = ly – β


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