Answer :
Given: A (a, b) and B (a1, b1) be the given points
To find:
Equation of the right bisector of the line segment joining the points (a, b) and (a1, b1).
Explanation:
Let C be the midpoint of AB.
∴ coordinates of C
And, slope of AB
So, the slope of the right bisector of AB is
Thus, the equation of the right bisector of the line segment joining the points (a, b) and (a1, b1) is
⇒ 2 (a1-a)x + 2y(b1-b) + (a2 + b2) – (a12 + b12) = 0
Hence, equation of the required line 2 (a1 – a)x + 2y(b1- b) + (a2 + b2) – (a12 + b12) = 0
Rate this question :
How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
view all courses
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation


RELATED QUESTIONS :
Find the equation
RS Aggarwal - MathematicsFind the equation
RS Aggarwal - MathematicsFind the equation
RS Aggarwal - MathematicsFind the equation
RD Sharma - MathematicsFind the equation
RD Sharma - MathematicsIf equation of th
RD Sharma - MathematicsFind the equation
RS Aggarwal - MathematicsFind the image of
RS Aggarwal - MathematicsA line passes thr
RD Sharma - Mathematics<span lang="EN-US
RS Aggarwal - Mathematics