Q. 115.0( 1 Vote )

# Find the equation

Given: A (a, b) and B (a1, b1) be the given points

To find:

Equation of the right bisector of the line segment joining the points (a, b) and (a1, b1).

Explanation:

Let C be the midpoint of AB.

coordinates of C

And, slope of AB

So, the slope of the right bisector of AB is

Thus, the equation of the right bisector of the line segment joining the points (a, b) and (a1, b1) is

2 (a1-a)x + 2y(b1-b) + (a2 + b2) – (a12 + b12) = 0

Hence, equation of the required line 2 (a1 – a)x + 2y(b1- b) + (a2 + b2) – (a12 + b12) = 0

Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation
view all courses
RELATED QUESTIONS :

Find the equationRS Aggarwal - Mathematics

Find the equationRS Aggarwal - Mathematics

Find the equationRS Aggarwal - Mathematics

Find the equationRD Sharma - Mathematics

Find the equationRD Sharma - Mathematics

If equation of thRD Sharma - Mathematics

Find the equationRS Aggarwal - Mathematics

Find the image ofRS Aggarwal - Mathematics

A line passes thrRD Sharma - Mathematics

<span lang="EN-USRS Aggarwal - Mathematics