Q. 115.0( 1 Vote )
Find the equation of the right bisector of the line segment joining the points (a, b) and (a1, b1).
Answer :
Given: A (a, b) and B (a1, b1) be the given points
To find:
Equation of the right bisector of the line segment joining the points (a, b) and (a1, b1).
Explanation:
Let C be the midpoint of AB.
∴ coordinates of C 
And, slope of AB 
So, the slope of the right bisector of AB is 
Thus, the equation of the right bisector of the line segment joining the points (a, b) and (a1, b1) is
⇒ 2 (a1-a)x + 2y(b1-b) + (a2 + b2) – (a12 + b12) = 0
Hence, equation of the required line 2 (a1 – a)x + 2y(b1- b) + (a2 + b2) – (a12 + b12) = 0
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