Answer :

Given: equation is parallel to 3x 4y + 5 = 0 and pass through (2, 3)


To find:


Equation of required line.


Explanation:


The equation of the line parallel to 3x 4y + 5 = 0 is


3x – 4y + λ = 0,


Where, λ is a constant.


It passes through (2, 3).


6 – 12 + λ = 0


λ = 6


Hence, the required line is 3x 4y + 6 = 0.


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