Answer :
Given: equation is parallel to 3x − 4y + 5 = 0 and pass through (2, 3)
To find:
Equation of required line.
Explanation:
The equation of the line parallel to 3x − 4y + 5 = 0 is
3x – 4y + λ = 0,
Where, λ is a constant.
It passes through (2, 3).
∴6 – 12 + λ = 0
⇒ λ = 6
Hence, the required line is 3x − 4y + 6 = 0.
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