Answer :
Given: equation is parallel to 3x − 4y + 5 = 0 and pass through (2, 3)
To find:
Equation of required line.
Explanation:
The equation of the line parallel to 3x − 4y + 5 = 0 is
3x – 4y + λ = 0,
Where, λ is a constant.
It passes through (2, 3).
∴6 – 12 + λ = 0
⇒ λ = 6
Hence, the required line is 3x − 4y + 6 = 0.
Rate this question :
How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
view all courses
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation
RELATED QUESTIONS :
Find the equation
RS Aggarwal - MathematicsFind the equation
RS Aggarwal - MathematicsFind the equation
RS Aggarwal - MathematicsFind the equation
RD Sharma - MathematicsFind the equation
RD Sharma - MathematicsIf equation of th
RD Sharma - MathematicsFind the equation
RS Aggarwal - MathematicsFind the image of
RS Aggarwal - MathematicsA line passes thr
RD Sharma - Mathematics<span lang="EN-US
RS Aggarwal - Mathematics