Answer :

It is given that the lines 3x + 4y = 5, 5x + 4y = 4 and λx + 4y = 6 meet at a point.


In other words, the given lines are concurrent.



3(- 24 + 16) – 4 (- 30 + 4λ) – 5 (20 – 4 λ) = 0


- 24 + 120 – 16 λ – 100 + 20 λ = 0


4 λ = 4


λ = 1

Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation
caricature
view all courses