Answer :
It is given that the lines 3x + 4y = 5, 5x + 4y = 4 and λx + 4y = 6 meet at a point.
In other words, the given lines are concurrent.
⇒ 3(- 24 + 16) – 4 (- 30 + 4λ) – 5 (20 – 4 λ) = 0
⇒ - 24 + 120 – 16 λ – 100 + 20 λ = 0
⇒ 4 λ = 4
⇒ λ = 1
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