Q. 2 A4.0( 5 Votes )
Find the coordinates of the vertices of a triangle, the equations of whose sides are :
x + y – 4 = 0, 2x – y + 3 0 and x – 3y + 2 = 0
Answer :
Given:
x + y − 4 = 0, 2x − y + 3 = 0 and x − 3y + 2 = 0
To find:
Point of intersection of pair of lines.
Concept Used:
Point of intersection of two lines.
Explanation:
x + y − 4 = 0 … (1)
2x − y + 3 = 0 … (2)
x − 3y + 2 = 0 … (3)
Solving (1) and (2) using cross - multiplication method:
⇒ x = 1/3, y = 11/3
Solving (1) and (3) using cross - multiplication method:
⇒ x = 5/2, y = 3/2
Similarly, solving (2) and (3) using cross - multiplication method:
⇒ x = - 7/5, y = 1/5
Hence, the coordinates of the vertices of the triangle are 
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