Q. 2 A4.0( 5 Votes )

# Find the coordinates of the vertices of a triangle, the equations of whose sides are :x + y – 4 = 0, 2x – y + 3 0 and x – 3y + 2 = 0

Given:

x + y − 4 = 0, 2x − y + 3 = 0 and x − 3y + 2 = 0

To find:

Point of intersection of pair of lines.

Concept Used:

Point of intersection of two lines.

Explanation:

x + y − 4 = 0 … (1)

2x − y + 3 = 0 … (2)

x − 3y + 2 = 0 … (3)

Solving (1) and (2) using cross - multiplication method:

x = 1/3, y = 11/3

Solving (1) and (3) using cross - multiplication method:

x = 5/2, y = 3/2

Similarly, solving (2) and (3) using cross - multiplication method:

x = - 7/5, y = 1/5

Hence, the coordinates of the vertices of the triangle are

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