Q. 31

In the given figu

Answer :

Given: ∠AOC = 100°

Here,

(Exterior ∠AOC) = 360° – (interior ∠AOC)

(Exterior ∠AOC) = 360° – 100°

(Exterior ∠AOC) = 260°

We know that,

(Exterior ∠AOC) = 2 × ∠ADC

260° = 2 × ∠ABC

∠ABC = = 130°

∴ ∠ABC = 130°

Here,

∠ABD = ∠ABC + ∠CBD

180° = 130° + ∠CBD

∠CBD = 180° – 130° = 50°

∴ ∠CBD = 50°

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