Q. 155.0( 1 Vote )

# In the given figu

Given: and Here,

In ΔAOB

OAB = OBA (angles opposite to equal sides are equal)

OBA = 30°

Now, by angle sum property

AOB + OBA + OAB = 180°

AOB + 30° + 30° = 180°

AOB = 180° – 30° – 30°

AOB = 120°

Now, Consider Δ BOC

OCB = OBC (angles opposite to equal sides are equal)

OBA = 55°

Now, by angle sum property

BOC + OBC + OCB = 180°

BOC + 55° + 55° = 180°

BOC = 180° – 55° – 55° = 70°

BOC = 70°

Here,

AOB = AOC + BOC

120° = AOC + 70°

AOC = 120° 70°

AOC = 50°

AOC = 50° Rate this question :

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