Answer :

Given: and


Here,


In ΔAOB


OA = OB (radius)


OAB = OBA (angles opposite to equal sides are equal)


OBA = 30°


Now, by angle sum property


AOB + OBA + OAB = 180°


AOB + 30° + 30° = 180°


AOB = 180° – 30° – 30°


AOB = 120°


Now, Consider Δ BOC


OC = OB (radius)


OCB = OBC (angles opposite to equal sides are equal)


OBA = 55°


Now, by angle sum property


BOC + OBC + OCB = 180°


BOC + 55° + 55° = 180°


BOC = 180° – 55° – 55° = 70°


BOC = 70°


Here,


AOB = AOC + BOC


120° = AOC + 70°


AOC = 120° 70°


AOC = 50°


AOC = 50°



Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation
caricature
view all courses
RELATED QUESTIONS :

Prove that there RS Aggarwal & V Aggarwal - Mathematics

Number of circlesRD Sharma - Mathematics

In the given figuRS Aggarwal & V Aggarwal - Mathematics

In the given figuRS Aggarwal & V Aggarwal - Mathematics

The question consRS Aggarwal & V Aggarwal - Mathematics

In the given figuRS Aggarwal & V Aggarwal - Mathematics

In the given figuRS Aggarwal & V Aggarwal - Mathematics

In the given figuRS Aggarwal & V Aggarwal - Mathematics

In the give figurRS Aggarwal & V Aggarwal - Mathematics

Prove that an angRS Aggarwal & V Aggarwal - Mathematics