PQ and RQ are the

Given: chords PQ and RQ are equidistant from center.

Here consider ΔPQS and ΔRQS

Here,

QS = QS (common)

QPS = QRS (right angle)

PQ = QS (chords equidistant from center are equal in length)

By RHS congruency ΔPQS ΔRQS

RQS = SQP and RSQ = QSP (by C.P.C.T)

Therefore we can say that diameter passing through Q bisects and

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