Answer :

Given: chords PQ and RQ are equidistant from center.


Here consider ΔPQS and ΔRQS


Here,


QS = QS (common)


QPS = QRS (right angle)


PQ = QS (chords equidistant from center are equal in length)


By RHS congruency ΔPQS ΔRQS


RQS = SQP and RSQ = QSP (by C.P.C.T)


Therefore we can say that diameter passing through Q bisects and


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