Answer :

Here,


In cyclic Quadrilateral ABFE


ABF + AEF = 180° (opposite angles in cyclic quadrilateral are supplementary) –1


In cyclic Quadrilateral ABCD


ABC + ADC = 180° (opposite angles in cyclic quadrilateral are supplementary) –2


From –1 and –2


ABF + AEF = ABC + ADC


AEF = ADC (ABF = ABC)


Since these are corresponding angles


We can say that EF || DC


EF||DC


Hence proved.


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