Answer :

DCB = (1/2) AOB [DCB = ACB]


DCB = (1/2) 40°


DCB = 2


In triangle BCD,


BDC + DCB + DBC = 180°[Sum of angles of triangle]


100° + 20° + OBC = 180°


120° + DBC = 180°


DBC = 60°


OBC = DBC = 60°


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