Q. 245.0( 1 Vote )

# In the give figure, and are two intersecting chords of a circle. If ∠CAB = 40° and ∠BCD = 80°, then ∠CBD = ?

A. 80^{o}

B. 60^{o}

C. 50^{o}

D. 70^{o}

Answer :

Given: and ∠BCD = 80°

Here,

∠CAB = ∠CDB = 40° ( angles in the same segment drawn from same chord are equal).

Now, in ΔBCD

By angle sum property

∠BCD + ∠CDB + ∠CBD = 180°

80° + 40° + ∠CBD = 180°

∠CBD = 180° – 40° – 80°

∠CBD = 60°

∴ ∠CBD = 60°

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