Q. 245.0( 1 Vote )

In the give figure, and are two intersecting chords of a circle. If CAB = 40° and BCD = 80°, then CBD = ?


A. 80o

B. 60o

C. 50o

D. 70o

Answer :

Given: and BCD = 80°


Here,


CAB = CDB = 40° ( angles in the same segment drawn from same chord are equal).


Now, in ΔBCD


By angle sum property


BCD + CDB + CBD = 180°


80° + 40° + CBD = 180°


CBD = 180° – 40° – 80°


CBD = 60°


CBD = 60°

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