Q. 15.0( 2 Votes )
In the given figure, ∠ECB = 40° and ∠CEB = 105°. Then, ∠EAD = ?
A. 50o
B. 35o
C. 20o
D. 40o
Answer :
Given: 
and 
Here,
∠ACB = ∠ADB = 40° (angles in same segment)
∠BEC = ∠AED = 105° (vertically opposite angles)
In ΔAED
By angle sum property
∠ADE + ∠AED + ∠EAD = 180°
40° + 105° + ∠EAD = 180°
∠EAD = 180° – 40° – 105° = 35°
∴ ∠EAD = 35°
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PREVIOUSFill in the blanks(i) Two circles having the same centre and different radii are called ________ circles.(ii) Diameter is the _________ chord of a circle.(iii) A continuous piece of a circle is called the ________ of the circle.(iv) An arc of a circle is called a __________ if the ends of the arc are the ends of a diameter.(v) A segment of a circle is the region between an arc and a ________ of the circle.(vi) A line segment joining the centre to any point on the circle is called its ________.NEXTIn the given figure, O is the centre of a circle, ∠AOB = 90° and ∠ABC = 30°. Then, ∠CAO = ?
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RELATED QUESTIONS :
In the given figure, O is the centre of a circle and ∠BCO = 30°. Find x and y.
In Fig. 16.135, O is the centre of the circle, Bo is the bisector of ∠ABC. Show that AB=AC.
In Fig. 16.121, it is given that O is the centre of the circle and ∠AOC=150°. Find ∠ABC.
