Q. 15.0( 2 Votes )

# In the given figure, ∠ECB = 40° and ∠CEB = 105°. Then, ∠EAD = ?

A. 50^{o}

B. 35^{o}

C. 20^{o}

D. 40^{o}

Answer :

Given: and

Here,

∠ACB = ∠ADB = 40° (angles in same segment)

∠BEC = ∠AED = 105° (vertically opposite angles)

In ΔAED

By angle sum property

∠ADE + ∠AED + ∠EAD = 180°

40° + 105° + ∠EAD = 180°

∠EAD = 180° – 40° – 105° = 35°

∴ ∠EAD = 35°

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