Answer :

Given: two circles having radii 6 cm and 3 cm


Construction: join AP


Consider ΔABP


Here,


AP2 = AB2 + BP2


52 = 42 + 32


25 = 16 + 9


25 = 25


ΔABP is right angled triangle


PQ = 2×BP


PQ = 2×3 = 6cm


PQ = 6cm

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