# <span lang="EN-US (i) Join OB.

OAB = OBA = 40°[Because OB = OA]

OCB = OBC = 30°[Because OB = OC]

ABC = OBA + OBC

ABC = 40°+ 30°

ABC = 70°

AOC = 2 × ABC

AOC = 2 × ABC

AOC = 2 × 70°

AOC = 14

(ii) BOC = 360° - (AOB + AOC) [Sum of all angles at a point = 360°]

BOC = 360° - (90° + 110°)

BOC = 360° - 200°

BOC = 160°

We know that BOC = 2 × BAC

BAC = (1/2) × BOC

BAC = (1/2) × 160°

BAC = 8

Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation view all courses RELATED QUESTIONS :

In Fig. 16.195, <RD Sharma - Mathematics

<span lang="EN-USRS Aggarwal & V Aggarwal - Mathematics

<span lang="EN-USRS Aggarwal & V Aggarwal - Mathematics

PQRS is a RD Sharma - Mathematics

ABCD is a RD Sharma - Mathematics

<span lang="EN-USRS Aggarwal & V Aggarwal - Mathematics

<span lang="EN-USRS Aggarwal & V Aggarwal - Mathematics

<span lang="EN-USRS Aggarwal & V Aggarwal - Mathematics

<span lang="EN-USRS Aggarwal & V Aggarwal - Mathematics

ABCD is a RD Sharma - Mathematics