Answer :
Let O be the point of intersection of the diagonals BD and AC of rectangle ABCD.
Since, the diagonals of a rectangle are equal and bisect each other.
∴ OA = OB = OC = OD
Hence, O is the center of the circle through A, B, C, D.
Rate this question :
How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
view all courses
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation


RELATED QUESTIONS :
In Fig. 16.195, <
RD Sharma - Mathematics<span lang="EN-US
RS Aggarwal & V Aggarwal - Mathematics<span lang="EN-US
RS Aggarwal & V Aggarwal - MathematicsPQRS is a
RD Sharma - MathematicsABCD is a
RD Sharma - Mathematics<span lang="EN-US
RS Aggarwal & V Aggarwal - Mathematics<span lang="EN-US
RS Aggarwal & V Aggarwal - Mathematics<span lang="EN-US
RS Aggarwal & V Aggarwal - Mathematics<span lang="EN-US
RS Aggarwal & V Aggarwal - MathematicsABCD is a
RD Sharma - Mathematics