Answer :

Given: CBE = 100°


Here,


ABE = ABC + CBE


180° = ABC + 100°


ABC = 180° – 100° = 80°


We know that,


In a cyclic quadrilateral opposite angles are supplementary


ABC + ADC = 180°


80° + ADC = 180°


ADC = 180° 80° = 100°


Here,


ADF = ADC + CDF


180° = 100° + CDF


CDF = 180° – 100° = 80°


CDF = 80°

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