# Find the length o

Length of the chord (AB) = x

distance of the chord from the centre is 9cm.

Draw a perpendicular bisector from center to the chord and name it OC.

AC = BC

Now in ∆ AOC

Using Pythagoras theorem

AO2 = AC2 + OC2

152 = AC2 + 92

AC2 = 152 – 92

AC2 = 225 – 81

AC2 = 144

AC = 12cm

BC = 12cm

The length of the chord is AC + BC = 12 + 12 = 24 cm.

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