Answer :

Given radius(AO) = 15cm

Length of the chord (AB) = x

distance of the chord from the centre is 9cm.

Draw a perpendicular bisector from center to the chord and name it OC.

AC = BC

Now in ∆ AOC

Using Pythagoras theorem

AO^{2} = AC^{2} + OC^{2}

15^{2} = AC^{2} + 9^{2}

AC^{2} = 15^{2} – 9^{2}

AC^{2} = 225 – 81

AC^{2} = 144

AC = 12cm

BC = 12cm

The length of the chord is AC + BC = 12 + 12 = 24 cm.

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