Q. 235.0( 1 Vote )
In the given figure, O is the centre of a circle and ∠OAB = 50°. Then, ∠CDA = ?
Given: ∠OAB = 50°
Construction: Join AC
OA = OB (radius)
∠OAB = ∠OBA (angles opposite to equal sides are equal)
∴ ∠OBA = 50°
∠OBA = ∠CDA (angles in the same segment)
∴ ∠CDA = 50°
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In the given figure, O is the centre of a circle and ∠BCO = 30°. Find x and y.
RS Aggarwal & V Aggarwal - Mathematics