Answer :


Draw, OPAB and OQCD


In triangle OBP and triangle OQC,


OPB = OQC [Angle = 90°]


OBP = OCD [Alternate angle]


OB = OC [Radius]


By side-angle-side criterion of congruence


ΔOBP ΔOQC


OP = OQ


The chords equidistant from the center are equal.


AB = CD Proved.


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