Q. 165.0( 1 Vote )

In the given figu

Answer :

Given: Two triangles ΔABC and ΔBCD, ∠BAC = 60° and ∠DBC = 50°

We know that ∠BAC = ∠BDC = 60° ( angles in the same segment drawn from same chord are

equal).

Now consider ΔBCD

By angle sum property

∠DBC + ∠BDC + ∠BCD = 180°

50° + 60° + ∠BCD = 180°

∠BCD = 180° – 50° – 60°

∠BCD = 70°

∴ ∠BCD = 70°

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