Answer :

Given: OAB = 50°


Consider ΔAOB


Here,


OA = OB (radius)


OAB = OBA = 50° (In a triangle, angles opposite to equal sides are equal)


By angle sum property


AOB + OAB + OBA = 180°


AOB + 50° + 50° = 180°


AOB = 180° – 50° – 50°


AOB = 80°


Here,


AOD = AOB + BOD


180° = 80° + BOD


BOD = 180° – 80° = 100°


BOD = 100°

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