Answer :
Given: ∠AOC = 120°
Construction: Join OD
We know that,
∠AOC = 2 × ∠ADC
120° = 2 ∠ADC
∠ADC = 60°
Here,
∠ADB = 90° (angle in a semicircle)
∠ADB = ∠ADC + ∠CDB = 90°
∠ADC + ∠CDB = 90°
60° + ∠CDB = 90°
∠CDB = 90° – 60°
∠CDB = 30°
∴ ∠BDC = 30°
Rate this question :
How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
view all courses
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation
RELATED QUESTIONS :
Prove that there
RS Aggarwal & V Aggarwal - MathematicsNumber of circles
RD Sharma - MathematicsIn the given figu
RS Aggarwal & V Aggarwal - MathematicsIn the given figu
RS Aggarwal & V Aggarwal - MathematicsThe question cons
RS Aggarwal & V Aggarwal - MathematicsIn the given figu
RS Aggarwal & V Aggarwal - MathematicsIn the given figu
RS Aggarwal & V Aggarwal - MathematicsIn the given figu
RS Aggarwal & V Aggarwal - MathematicsIn the give figur
RS Aggarwal & V Aggarwal - MathematicsProve that an ang
RS Aggarwal & V Aggarwal - Mathematics