# In the given figu

Given: CE = ED = 8 cm and EB = 4 cm

Construction: Join OC (OC is radius)

Let AB = 2x (diameter)

OB = OC = x (radius)

In Δ COE

CO2 = CE2 + OE2

x2 = 82 + (OB – EB)2

x2 = 82 + (x – 4)2

x2 = 82 + x2 + 42 – 2(x)(4)

x2 = 64+ x2 + 16 – 8x

8x = 64+ 16 + x2 – x2

8x = 80

x = = 10

Radius = x = 10 cm

Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Related Videos  IMP Qs Related with Circles For Boards44 mins  Arc of Circle And Related IMP Qs40 mins  Chords Of Circles42 mins  IMP Theorems And Their Application43 mins  Circles- All kinds of Questions36 mins
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation view all courses RELATED QUESTIONS :

PQ and RQ are theRS Aggarwal & V Aggarwal - Mathematics

In a circle of raRD Sharma - Mathematics

Two equal circlesRD Sharma - Mathematics

Angle formed in mRD Sharma - Mathematics

If AB is aRD Sharma - Mathematics

The greatest chorRD Sharma - Mathematics

If two diameters RD Sharma - Mathematics

<span lang="EN-USRS Aggarwal & V Aggarwal - Mathematics