Answer :
Given: BOC is the diameter of the circle
AB = AC
Here, BAC forms a semicircle.
We know that angle in a semicircle is always 90
BAC = 90
Here ABC =
ACB (since angles opposite equal sides are equal in a triangle)
We know that sum of all the angles in the triangle is 180
That is
ABC +
ACB +
BAC = 180
⇒ 2 × ABC +
BAC = 180
⇒ 2 × ABC + 90 = 180
⇒ 2 × ABC = 180
– 90
⇒ 2 ×ABC = 90
⇒ ABC = 45
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