Let distance OC = 8 cmChord AB = 30 cmDraw OCABTherefore,OC bisects AB at CAC = (1/2) AB⇒ AC = (1/2) 30⇒ AC = 15 cmIn triangle OCA,OA2 = OC2 + AC2⇒ OA2 = 82 + 152⇒ OA2= 64 + 225⇒ OA2= 289⇒ OA = 17 cmHence, radius of the circle = 17 cm.

Q. 34.0( 19 Votes )

<span lang="EN-US

Class 9th RS Aggarwal & V Aggarwal - Mathematics 11. Circles

Answer :

Let distance OC = 8 cm

Chord AB = 30 cm

Draw OCAB

Therefore,

OC bisects AB at C

AC = (1/2) AB

⇒ AC = (1/2) 30

⇒ AC = 15 cm

In triangle OCA,

OA² = OC² + AC²

⇒ OA² = 8² + 15²

⇒ OA²= 64 + 225

⇒ OA²= 289

⇒ OA = 17 cm

Hence, radius of the circle = 17 cm.

Rate this question :

How useful is this solution?

We strive to provide quality solutions. Please rate us to serve you better.

PREVIOUS<span lang="EN-US NEXT<span lang="EN-US

Related Videos

Tips to Solve RD Sharma Problems Faster23 mins

Smart Revision | Most Important Questions of Circles45 mins

RD Sharma | Extra Qs. of Cyclic Quadrilaterals31 mins

Smart Revision | World of Circles44 mins

NCERT | Imp Qs Discussion on Circles39 mins

Smart Revision | Chords and Related Concepts42 mins

Let's Solve Good Questions on Circle41 mins

Some Imp Concepts Of Circles44 mins

NCERT | Imp. Qs. on Circles43 mins

Bonus Questions on Circles37 mins

Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts

Dedicated counsellor for each student

24X7 Doubt Resolution

Daily Report Card

Detailed Performance Evaluation

view all courses