Answer :
Let distance OC = 8 cm
Chord AB = 30 cm
Draw OCAB
Therefore,
OC bisects AB at C
AC = (1/2) AB
⇒ AC = (1/2) 30
⇒ AC = 15 cm
In triangle OCA,
OA2 = OC2 + AC2
⇒ OA2 = 82 + 152
⇒ OA2= 64 + 225
⇒ OA2= 289
⇒ OA = 17 cm
Hence, radius of the circle = 17 cm.
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