Answer :


Let distance OC = 8 cm


Chord AB = 30 cm


Draw OCAB


Therefore,


OC bisects AB at C


AC = (1/2) AB


AC = (1/2) 30


AC = 15 cm


In triangle OCA,


OA2 = OC2 + AC2


OA2 = 82 + 152


OA2= 64 + 225


OA2= 289


OA = 17 cm


Hence, radius of the circle = 17 cm.


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