# <span lang="EN-US

Let ABC be an equilateral triangle of side 9 cm.

And AD be one of its medians.

Then,

BD = (1/2) BC

BD = (1/2) 9 = 4.5 cm

In an equilateral triangle the centroid and circumcenter coincide and AO: OD = 2: 1

= (2/3) (9√3)/2

= 3√3 cm

Hence, radius of circle = 3√3 cm.

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