# In the given figu

Given: is a cyclic quadrilateral, CF||AB, and

Here, CF|| AB

Hence BC is transversal

ABC = BCF = 85° (Alternate interior angles)

Here,

DCB + BCF + ECF = DCE

DCB + 85° + 20° = 180°

DCB = 180° – 85° – 20° = 75°

We know that,

In a cyclic quadrilateral opposite angles are supplementary

BAD = 180° 75° = 105°

Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Related Videos
Arc of Circle And Related IMP Qs40 mins
IMP Qs Related with Circles For Boards44 mins
Chords Of Circles42 mins
IMP Theorems And Their Application43 mins
Circles- All kinds of Questions36 mins
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation
view all courses
RELATED QUESTIONS :

In Fig. 16.195, <RD Sharma - Mathematics

<span lang="EN-USRS Aggarwal & V Aggarwal - Mathematics

<span lang="EN-USRS Aggarwal & V Aggarwal - Mathematics

PQRS is a RD Sharma - Mathematics

ABCD is a RD Sharma - Mathematics

<span lang="EN-USRS Aggarwal & V Aggarwal - Mathematics

<span lang="EN-USRS Aggarwal & V Aggarwal - Mathematics

<span lang="EN-USRS Aggarwal & V Aggarwal - Mathematics

<span lang="EN-USRS Aggarwal & V Aggarwal - Mathematics

ABCD is a RD Sharma - Mathematics