Q. 113.7( 3 Votes )
In the given figure, AOC is a diameter of a circle with centre O and arc 
arc BYC. Find ∠BOC.
Answer :
Given: 
arc 
Here,
2×AXB = BYC
∴ 2×∠AOB = ∠BOC
∠AOB = 
∠BOC –1
Here,
∠AOC = ∠AOB + ∠BOC = 180°
∠BOC + ∠BOC = 180° (from –1)
∠BOC = 180°
∠BOC = 
×180° = 120°
∴
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RELATED QUESTIONS :
In the given figure, O is the centre of a circle and ∠BCO = 30°. Find x and y.
