Answer :
Given: arc
Here,
2×AXB = BYC
∴ 2×∠AOB = ∠BOC
∠AOB = ∠BOC –1
Here,
∠AOC = ∠AOB + ∠BOC = 180°
∠BOC + ∠BOC = 180° (from –1)
∠BOC = 180°
∠BOC = ×180° = 120°
∴
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