# <span lang="EN-US

(i)

In triangle CDE,

CDE + CED + DCE = 180°[Sum of angles of triangle]

40° + 90° + DCE = 180°

130° + DCE = 180°

DCE = 50°

(ii)

AOC + BOC = 180°[Because AOB is a straight line]

80° + BOC = 180°

BOC = 100°

In triangle BOC,

OCB + BOC + OBC = 180°[Sum of angles of triangle]

50° + 100° + OBC = 180°[DCE = 50°]

150° + OBC = 180°

OBC = 30°

ABC = OBC = 30°

Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation
view all courses
RELATED QUESTIONS :

Prove that there RS Aggarwal & V Aggarwal - Mathematics

Number of circlesRD Sharma - Mathematics

In the given figuRS Aggarwal & V Aggarwal - Mathematics

In the given figuRS Aggarwal & V Aggarwal - Mathematics

The question consRS Aggarwal & V Aggarwal - Mathematics

In the given figuRS Aggarwal & V Aggarwal - Mathematics

In the given figuRS Aggarwal & V Aggarwal - Mathematics

In the given figuRS Aggarwal & V Aggarwal - Mathematics

In the give figurRS Aggarwal & V Aggarwal - Mathematics

Prove that an angRS Aggarwal & V Aggarwal - Mathematics