Answer :

(i)


In triangle CDE,


CDE + CED + DCE = 180°[Sum of angles of triangle]


40° + 90° + DCE = 180°


130° + DCE = 180°


DCE = 50°


(ii)


AOC + BOC = 180°[Because AOB is a straight line]


80° + BOC = 180°


BOC = 100°


In triangle BOC,


OCB + BOC + OBC = 180°[Sum of angles of triangle]


50° + 100° + OBC = 180°[DCE = 50°]


150° + OBC = 180°


OBC = 30°


ABC = OBC = 30°


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