# <span lang="EN-US

(i) ∠AOC + AOB = 180°[Because BC is a straight line]

AOC + 70°= 180°

AOC + 70°= 180°

AOC = 110°

OAC = OCA ________________ (i)

In triangle AOC,

OAC + OCA + AOC = 180°[Sum of angles of triangle]

2 OCA + 110° = 180°[From equation (i)]

2 OCA = 70°

2 OCA = 70°

OCA = 35°

(ii) AOC + AOB = 180°[Because BC is a straight line]

AOC + 70°= 180°

AOC + 70°= 180°

AOC = 110°

OAC = OCA ________________ (i)

In triangle AOC,

OAC + OCA + AOC = 180°[Sum of angles of triangle]

2 OAC + 110° = 180°[From equation (i)]

2 OAC = 70°

2 OAC = 70°

OAC = 35°

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