Q. 2

In the given figu

Given: and

We know that,

AOB = 2× ACB

AOB = ACB

×90° = ACB

ACB = 45°

Now, consider ΔABC

By angle sum property

ACB + ABC + CAB = 180°

45° + 30° + CAB = 180°

CAB = 180° — 45° — 30° = 105°

Consider ΔAOB

Here,

Let OA = OB = x

By angle sum property

AOB + OAB + OBA = 180°

90° + x + x = 180°

2x = 180° – 90° = 90°

x = 45°

Now,

CAB = BAO + CAO = 105°

CAO = 105° – 45° = 60°

CAO = 60°

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