Answer :

Given: OAB = 20° and OCB = 50°


Here,


In ΔAOB


OA = OB (radius)


OAB = OBA (angles opposite to equal sides are equal)


OBA = 20°


Now, by angle sum property


AOB + OBA + OAB = 180°


AOB + 20° + 20° = 180°


AOB = 180° – 20° – 20°


AOB = 140°


Now, Consider Δ BOC


OC = OB (radius)


OCB = OBC (angles opposite to equal sides are equal)


OBA = 50°


Now, by angle sum property


COB + OBC + OCB = 180°


COB + 50° + 50° = 180°


COB = 180° – 50° – 50°


COB = 80°


Here,


AOB = AOC + COB


140° = AOC + 80°


AOC = 140° 80°


AOC = 60°


AOC = 60°

Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation
caricature
view all courses
RELATED QUESTIONS :

Prove that there RS Aggarwal & V Aggarwal - Mathematics

Number of circlesRD Sharma - Mathematics

In the given figuRS Aggarwal & V Aggarwal - Mathematics

In the given figuRS Aggarwal & V Aggarwal - Mathematics

The question consRS Aggarwal & V Aggarwal - Mathematics

In the given figuRS Aggarwal & V Aggarwal - Mathematics

In the given figuRS Aggarwal & V Aggarwal - Mathematics

In the given figuRS Aggarwal & V Aggarwal - Mathematics

In the give figurRS Aggarwal & V Aggarwal - Mathematics

Prove that an angRS Aggarwal & V Aggarwal - Mathematics