Answer :

Given: ΔABS is equilateral


In ΔABC


BAC = 60° (All angles in equilateral triangle are equal to 60°)


We know that,


In a cyclic quadrilateral opposite angles are supplementary


BAC + BDC = 180°


60° + BDC = 180°


BDC = 180° 60° = 120°


BDC = 120°

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