Q. 345.0( 1 Vote )

In the given figu

Answer :

Given: ΔABS is equilateral

In ΔABC

∠BAC = 60° (All angles in equilateral triangle are equal to 60°)

We know that,

In a cyclic quadrilateral opposite angles are supplementary

∴ ∠BAC + ∠BDC = 180°

60° + ∠BDC = 180°

∠BDC = 180° – 60° = 120°

∴ ∠BDC = 120°

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