Answer :
ABCD is cyclic quadrilateral.
∴ ∠ABC + ∠ADC = 180°
⇒ 92° + ∠ADC = 180°
⇒ ∠ADC = 88°
AE || CD
∴∠EAD = ∠ADC = 88°
Now,
∠BCD = 180° - ∠DAB
⇒ ∠BCD = ∠DAF = ∠EAD + ∠EAF
⇒ ∠BCD = 88° + 20°
⇒ ∠BCD = 108°
Rate this question :
How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
view all courses
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation
RELATED QUESTIONS :
In Fig. 16.195, <
RD Sharma - Mathematics<span lang="EN-US
RS Aggarwal & V Aggarwal - Mathematics<span lang="EN-US
RS Aggarwal & V Aggarwal - MathematicsPQRS is a
RD Sharma - MathematicsABCD is a
RD Sharma - Mathematics<span lang="EN-US
RS Aggarwal & V Aggarwal - Mathematics<span lang="EN-US
RS Aggarwal & V Aggarwal - Mathematics<span lang="EN-US
RS Aggarwal & V Aggarwal - Mathematics<span lang="EN-US
RS Aggarwal & V Aggarwal - MathematicsABCD is a
RD Sharma - Mathematics