# Two chords AB <sp

Given: AB = 11cm, BE = 3cm and DE = 3.5cm

Construction: Join AC

Here,

AE: CE = DE: BE

AE×BE = DE×CE

(AB + BE)×BE = DE×(CD + DE)

(11 + 3)×3 = 3.5×(CD + 3.5)

14×3 = 3.5×(CD + 3.5)

3.5×(CD + 3.5) = 42

(CD + 3.5) = = 12

CD = 12—3.5 = 8.5

CD = 8.5

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