# The radius of a c

Length of the chord (AB) = 10cm

Draw a perpendicular bisector from center to the chord and name it OC.

AC = BC = 5cm

Now in ∆ AOC,

Using Pythagoras theorem

AO2 = AC2 + OC2

132 = 52 + OC2

OC2 = 132 – 52

OC2 = 169 – 25

OC2 = 144

OC = 12cm

The distance of the chord from the centre is 12cm.

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