Q. 255.0( 1 Vote )

In the given figure, O is the centre of a circle and chords AC and BD intersect at E. If AEB = 110° and CBE = 30° then ADB = ?


A. 70o

B. 60o

C. 80o

D. 90o

Answer :

Given: AEB = 110° and CBE = 30°


AEC = AEB + BEC = 180°


AEB + BEC = 180°


110° + BEC = 180°


BEC = 180° – 110°


BEC = 70°


In ΔBEC


By angle sum property


CBE + BEC + ECB = 180°


30° + 70° + ECB = 180°


ECB = 180° – 30° – 70°


ECB = 80°


Here,


ECB = ADB (angles in the same segment)


ECB = ADB = 80°


ADB = 80°

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