# <span lang="EN-US

Let AB be a chord of a circle with center O. OC AB, then

AB = 16 cm, and OA = 10 cm. OC AB

Therefore,

OC bisects AB at C

AC = (1/2) AB

AC = (1/2) 16

AC = 8 cm

In triangle OAC,

OA2 = OC2 + AC2

102 = OC2 + 82

100 = OC2 + 64

OC2= 36

OC= 6

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