Q. 14.1( 49 Votes )

<span lang="EN-US

Answer :

Let AB be a chord of a circle with center O. OCAB, then

AB = 16 cm, and OA = 10 cm.

OCAB

Therefore,

OC bisects AB at C

AC = (1/2) AB

⇒ AC = (1/2) 16

⇒ AC = 8 cm

In triangle OAC,

OA² = OC² + AC²

⇒ 10² = OC² + 8²

⇒ 100 = OC² + 64

⇒ OC²= 36

⇒ OC= 6

Rate this question :

How useful is this solution?

We strive to provide quality solutions. Please rate us to serve you better.

Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts

Dedicated counsellor for each student

24X7 Doubt Resolution

Daily Report Card

Detailed Performance Evaluation