# <span lang="EN-US

Let radius OA = OC = 17 cm

Chord AB = 30 cm and CD = 16 cm Draw OL and OM

Therefore,

AP = (1/2) AB

AP = (1/2) 30 = 15 cm

CQ = (1/2) CD

CQ = (1/2) 16 = 8 cm

In triangle OAP,

OP2 = OA2 - AP2

OP2 = 172 - 152

OP2= 289 - 225

OP2= 64

OP = 8 cm

In triangle OQD,

OQ2 = OC2 - CQ2

OQ2 = 172 - 82

OQ2= 289 - 64

OQ2= 225

OQ = 15 cm

Now,

PQ = OP + OQ = 8 + 15 = 23

Hence, distance between chords = 23 cm.

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