Answer :

Given: and OD = 6cm


Here OB is radius


Let OB = x cm


In ΔBOD, By Pythagoras theorem


OB2 = BD2 + OD2


x2 = BD2 + 62


x2 = BD2 + 36


BD2 = x2 – 36


Now consider Δ ABC


Here BC = 2x


By Pythagoras theorem


BC2 = AB2 + AC2


(2x)2 = 4(x2 – 36)+ AC2


4x2 = 4x2 –144 + AC2


AC2 = 144


AC = 12 cm


AC = 12 cm

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