Answer :

Given: ABCD is cyclic quadrilateral and ADC = 120°


Here,


ADC + ABC = 180° (opposite angles in cyclic quadrilateral are supplementary)


120° + ABC = 180°


ABC = 180° – 120°


ABC = 60°


Here,


ACB = 90° (angle in semicircle)


Now, consider ΔABC


By angle sum property


BAC + ABC + ACB = 180°


BAC + 60° + 90° = 180°


BAC = 180° – 60° – 90°


BAC = 30°

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