Q. 75.0( 2 Votes )

# AB and CD are two equal chords of a circle with centre O such that ∠AOB = 80°, then ∠COD = ?

A. 100^{o}

B. 80^{o}

C. 120^{o}

D. 40^{o}

Answer :

Given:

AB = CD

We know that angles subtended from equal chords at center are equal.

∴ ∠ AOB = ∠ COD

∴ ∠ COD = 80°

Rate this question :

PQ and RQ are the chords of a circle equidistant from the centre. Prove that the diameter passing through Q bisects ∠PQR and ∠PSR.

RS Aggarwal & V Aggarwal - Mathematics

The radius of a circle is 8 cm and the length of one of its chords is 12 cm. Find the distance of the chord from the centre.

RD Sharma - MathematicsIn the given figure, is the center of a circle in which chords and intersect at such that bisects Prove that

RS Aggarwal & V Aggarwal - Mathematics

Prove that the diameter of a circle perpendicular to one of the two parallel chords of a circle is perpendicular to the other and bisects it.

RS Aggarwal & V Aggarwal - Mathematics

In a circle of radius 17 cm, two parallel chords are drawn on opposite side of a diameter. The distance between the chords is 23 cm. If the length of one chord is 16 cm, then the length of the other is

RD Sharma - MathematicsTwo equal circles of radius *r* intersect such that each passes through the centre of the other. The length of the common chord of the circles is

Angle formed in minor segment of a circle is

RD Sharma - Mathematics