Answer :

OA = OB [Radius]


OAB = OBC = 50°


In triangle AOB,


AOB + OAB + OBC = 180°[Sum of angles of triangle]


AOB + 50° + 50° = 180°


AOB + 100° = 180°


AOB = 80°


x = 180° AOB [AOD is a straight line]


x = 180°- 80°


x = 100°


X + Y = 180°[Opposite angle of a cyclic quadrilateral are supplementary]


100° + Y = 180°


Y = 80°


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