Q. 11

# <span lang="EN-US

OA = OB [Radius]

OAB = OBC = 50°

In triangle AOB,

AOB + OAB + OBC = 180°[Sum of angles of triangle]

AOB + 50° + 50° = 180°

AOB + 100° = 180°

AOB = 80°

x = 180° AOB [AOD is a straight line]

x = 180°- 80°

x = 100°

X + Y = 180°[Opposite angle of a cyclic quadrilateral are supplementary]

100° + Y = 180°

Y = 80°

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