# In the given figu

Given: BC = OB and ACD = 25°

Here in Δ OBC

BOC = BCO (angles opposite to equal sides are equal)

BOC = 25°

By angle sum property

BOC + BCO + OBC = 180°

25° + 25° + OBC = 180°

50° + OBC = 180°

OBC = 180° – 50°

OBC = 130°

Here

ABC = ABO + OBC = 180°

ABO + 130° = 180°

ABO = 180° – 130°

ABO = 50°

Now, in ΔAOB

ABO = BAO = 50° (angles opposite to equal sides are equal)

By angle sum property

ABO + BAO + AOB = 180°

50° + 50° + AOB = 180°

AOB = 180° – (50° + 50°) = 180° – 100° = 80°

AOB = 80°

Here

DOC = AOD + AOB + BOC = 180°

AOD + 80° + 25° = 180°

AOD + 105° = 180°

AOD = 180° 105°

AOD = 75°

AOD = 75°

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