# In the given figu

Given: CB = CD and CBD = 35°

Consider ΔBCD

Here,

CB = CD (given)

CBD = CDB = 35° (In a triangle, angles opposite to equal sides are equal)

By angle sum property

BCD + CBD + CDB = 180°

BCD + 35° + 35° = 180°

BCD = 180° – 35° – 35° = 110°

We know that,

In a cyclic quadrilateral opposite angles are supplementary

BAD = 180° 110° = 70°

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