Q. 293.8( 4 Votes )

# <span lang="EN-US

(i) BDA = 90°= EDB [Semi circle angle]

In triangle EBD,

DBE + EDB + BED = 180°

DBE + 90° + 25° = 180°

DBE + 115° = 180°

DBE = 65°

Now,

DBC + DBE = 180°[CBE is a straight line]

DBC + 65° = 180°

DBC = 115°

(ii) DCB = BAD [Angle in the same segment]

DCB = 35°

(iii) BDC = 30°

In triangle BCD,

BDC + DCB + DBC = 180°

BDC + 35° + 115° = 180°

BDC + 150° = 180°

BDC = 30°

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