Answer :


Construction: Join AE


Consider cyclic quadrilateral ACDEA


Here,


ACD + DEA = 180° (opposite angles in cyclic quadrilateral are supplementary)


Also,


AEB = 90° (angle in semicircle)


∴∠ACD + DEA + AEB = 180° + 90°


ACD + BED = 270° (DEA + AEB = BED)


∴∠ACD + BED = 270°


Hence proved.


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