Q. 6

In the given figure, AOB is a diameter of a circle with centre O such that AB = 34 cm and CD is a chord of length 30 cm. Then, the distance of CD from AB is


A. 8 cm

B. 15 cm

C. 18 cm

D. 6 cm

Answer :

Given: AB 34 cm and CD = 30 cm


Here OL is the perpendicular bisector to CD


CL = LD = 15 cm


Construction: Join OD(radius)


OD = 17cm


Now in Δ ODL


By Pythagoras theorem


OD2 = OL2 + LD2


172 = OL2 + 152


OL2 = 172 + 152


OL2 = 289—225


OL2 = 64


OL = 8


The distance of from is = OL = 8cm

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