Q. 6

# In the given figu

Given: AB 34 cm and CD = 30 cm

Here OL is the perpendicular bisector to CD

CL = LD = 15 cm

OD = 17cm

Now in Δ ODL

By Pythagoras theorem

OD2 = OL2 + LD2

172 = OL2 + 152

OL2 = 172 + 152

OL2 = 289—225

OL2 = 64

OL = 8

The distance of from is = OL = 8cm

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