Let distance OC = 3 cmRadius = OA = 5 cmDraw OCABIn triangle OCA,OA2 = OC2 + AC2⇒ 52 = 32 + AC2⇒ AC2= 16⇒ AC = 4 cm __________________ (i)Now,AB = 2 AC⇒ AB = 8 cm [From equation (i)]Hence, length of a chord = 8 cm.

Q. 24.4( 25 Votes )

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Class 9th RS Aggarwal & V Aggarwal - Mathematics 11. Circles

Answer :

Let distance OC = 3 cm

Radius = OA = 5 cm

Draw OCAB

In triangle OCA,

OA² = OC² + AC²

⇒ 5² = 3² + AC²

⇒ AC²= 16

⇒ AC = 4 cm __________________ (i)

Now,

AB = 2 AC

⇒ AB = 8 cm [From equation (i)]

Hence, length of a chord = 8 cm.

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