Let distance OC = 3 cmRadius = OA = 5 cmDraw OCABIn triangle OCA,OA2 = OC2 + AC2⇒ 52 = 32 + AC2⇒ AC2= 16⇒ AC = 4 cm __________________ (i)Now,AB = 2 AC⇒ AB = 8 cm [From equation (i)]Hence, length of a chord = 8 cm.

Q. 24.4( 25 Votes )

<span lang="EN-US

Class 9th RS Aggarwal & V Aggarwal - Mathematics 11. Circles

Answer :

Let distance OC = 3 cm

Radius = OA = 5 cm

Draw OCAB

In triangle OCA,

OA² = OC² + AC²

⇒ 5² = 3² + AC²

⇒ AC²= 16

⇒ AC = 4 cm __________________ (i)

Now,

AB = 2 AC

⇒ AB = 8 cm [From equation (i)]

Hence, length of a chord = 8 cm.

Rate this question :

How useful is this solution?

We strive to provide quality solutions. Please rate us to serve you better.

PREVIOUS<span lang="EN-US NEXT<span lang="EN-US

Related Videos

IMP Qs Related with Circles For Boards44 mins

Arc of Circle And Related IMP Qs40 mins

Chords Of Circles42 mins

IMP Theorems And Their Application43 mins

Circles- All kinds of Questions36 mins

Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts

Dedicated counsellor for each student

24X7 Doubt Resolution

Daily Report Card

Detailed Performance Evaluation

view all courses