Answer :


Let distance OC = 3 cm


Radius = OA = 5 cm


Draw OCAB


In triangle OCA,


OA2 = OC2 + AC2


52 = 32 + AC2


AC2= 16


AC = 4 cm __________________ (i)


Now,


AB = 2 AC


AB = 8 cm [From equation (i)]


Hence, length of a chord = 8 cm.


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