# In the given figu

Given: AB = AC

Construction: join OA, OB and OC

Proof:

Consider ΔAOB and ΔAOC

Here,

OA = OA (common)

AB = AC (given)

By SSS congruency

ΔAOB ΔAOC

OAC = OAB (by C.P.C.T)

Hence, we can say that OA is the bisector of BAC, that is O lies on the bisector of BAC.

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